python - How can I use Ajax to check the status and result of a django-celery task? - Stack Overflow: "To access these URLs, you need to include them from one of your urls.py files. For example:
urlpatterns = patterns('',
url('^tasks/', include('djcelery.urls')),
)
You would then access them using, for example, http://example.com/tasks/{{ task_id }}/status/."
'via Blog this'
